perfect chemistry series

public static string format (string jsonstr) {Int. level = 0; StringBuffer jsonformatstr = new StringBuffer (); for (int i=0;iWith the format code above, you can make your JSON print flawlessly.Example is still the bean to JSON blog post example{"Addresses": [{"Address": "Address1", "sametest": [{"Addresses": [], "age": 0, "attrs": null, "baseaddress": null, " BirthDay ": null," EMPTYSTR ":" "," Live ": false," name ":" Samename "," Nullstr ":" "," sametest ": null}]},{" Address

Json Series 3 allows you to print the perfect json format Public static String format (String jsonStr) {int level = 0; StringBuffer jsonForMatStr = new StringBuffer (); for (int I = 0; I 0 '\ n' = jsonForMatStr. charAt (jsonForMatStr. length ()-1) {jsonForMatStr. append (getLevelStr (level);} switch (c) {case '{': case '[': jsonForMatStr. append (c + "\ n"); level ++; break; case ',': jsonForMatStr. a

Title Link: http://acm.hdu.edu.cn/showproblem.php?pid=4513Test instructions than the longest palindrome string more than a front of the person is lower than the person below this condition, so in p[i]++ time to judge S[i-p[i]]Using the longest palindrome string algorithm manacher: Set a template on it;#include #includestring.h>#includeusing namespacestd;Const intN = 2e5+7;intP[n];intS[n];intManacher (intS[],intN) { intId=0, mx =0, ans =0; for(intI=2; i) { if(MX >i) p[i]= Min (p[id*

1, find a longest palindrome substring, require the middle of the value of the largest, and then to the sides of the decrement.2. The judging condition should be changed to: ma[i+mp[i]]==ma[i-mp[i]]ma[i-mp[i]]3.#include #include#includestring.h>using namespacestd;//find the longest palindrome stringConst intmaxn=100005;intma[maxn*2];intmp[maxn*2];voidManacher (intS[],intLen) { intL=0; Ma[l++]=-1;//flag ' $ 'ma[l++]=255;//sign ' # ' for(intI=0; i) {ma[l++]=S[i]; Ma[l++]=255; } Ma[l]=1;//si

First of all, to learn the longest common ascending subsequence LCIs, and then to optimize the algorithm for n*n efficiency, it is important to note that there can be a maximum in the middle of the sequence that can be obtained. Just beginning to reverse the input array, write down to find that there may be a problem. But the specifics are not carefully understood.#include using namespace STD;intdp[ -][ -],a[ -];intMain () {intN,_,i,j,k,ans,mx,t;scanf("%d", _); while(_--) {scanf("%d", n); for(i=

On Android6.0, the following code is used:Intent Intent = new Intent () intent.setaction ("Xxx.server"); Bindservice (Intent, Mconn, context.bind_auto_create);The exception that prompted the warning:Implicit intents with StartService is not safeCheck the source code, the original 5.0 must be forced to use the display mode to start the service.private void Validateserviceintent (Intent service) { if (service.getcomponent () = = NULL Service.getpackage () = null) { if (Getapplic

Analysis: The problem can be solved by the method of finding the longest palindrome string, the longest palindrome string using the Manacher algorithm, O (n) time complexity.Note: while (A[i-len[i]]==a[i+len[i]] a[i-len[i]]#include HDU ACM 4513 Series Story--Perfect formation ii-> find the longest palindrome (Manacher algorithm)